Casino Roulette Game Analysis (Odds and Results Analysis)

Edwerk wrote: Therefore, it's not the indentation that's important, but the calculation of how many numbers will be included in the forecast for each full cycle. I recommend [always] more than one number. Place bets no more times than the number of numbers entered.

+1000

Here's a specific example of a session with Evo Roulette for 63 spins (up to 100 spins is a regular game):

29. 14. 27. 5. 9. 16. 8. 0. 28. 9. 7. 36. 10. 9. 24. 18. 16. 12. 23. 29. 27. 26. 17. 14. 36. 2. 21. 7. 34. 24. 36. 34. 29. 29. 30. 20. 21. 3. 14. 31. 1. 1. 35. 35. 3. 20. 5. 22. 29. 18. 5. 26. 0. 10. 25. 12. 1. 36. 14. 22. 18. 25. 2. 5

What obvious moments could the player catch?

29. 14. 27. 5. 9. 16. 8. 0. 28. 9. 7. 36. 10. 9. 24. 18. 16. 12. 23. 29. 27. 26. 17. 14. 36. 2. 21. 7. 34. 24. 36. 34. 29. 29. 30. 20. 21. 3. 14. 31. 1. 1. 35. 35. 3. 20. 5. 22. 29. 18. 5. 26. 0. 10. 25. 12. 1. 36. 14. 22. 18. 25. 2. 5

This is a simple repeat game of +/- 2 numbers on the field and along the track from the last one drawn. This hot game is simple and clear. All statistics can be viewed without any additional tools. For a 63-spin session, the number of Ws is more than enough to multiply the credit.

For now, let's look at this specific strategy as an example.
On average, the bet is 9 numbers, sometimes less (numbers on the field and track are duplicated).

WL chain
- - - - - - - - - - +
- - +
- - - - - - +
+
- - - - +
- - - - +
- +
+
- - - - +
- +
- +
+
- - - +
+
- - +
- - - - +
- - +
- +
-

The beginning was difficult (10L), then a calm period of the game.

It is obvious that for a bet of 9 numbers it is easy to calculate the probability of winning:
P = 9/37 = 0.243
This probability is constant for any spin session and does not depend on history.
/the opinion of official mathematics/

Probability of throwing heads 1 time in 1 toss: P = 0.5
The probability of throwing heads at least once in 2 throws: P = 3/4 = 0.75
- -
- +
+ -
+ +
Probability of NOT getting heads in 1 throw: P=(1-0.5)
The probability of NOT throwing heads N times in a row: P = (1-0.5)^N

Now let's write out the W/L chain in terms of probabilities.

Session 10L Start:
- - - - - - - - - - +
(1-0.243)^10

0.757
0.573049
0.433798093
0.328385156
0.248587563
0.188180785
0.142452855
0.107836811
0.081632466
0.061795777
W