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I tried it once. Did I understand correctly or was I just lucky? Log-1.jpg By the way, at the very beginning, if I understood correctly, 9+1 should be like 10. 1=L5 came up. (Or is it R5?) :pinch: Then 1 came up. +1 = 2 + L5 = 32 should come up. 15 came up, the ball would have just come to us. But...

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Hyperspace and Wormholes

  • klick
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Hyperspace and Wormholes

1 month 3 weeks ago - 1 month 3 weeks ago
#1
When we look at the bets in the plane, for example, a bet of a dozen on one spin. 12 numbers are activated simultaneously in the plane. We can turn the plane edgewise to the observer and add time layers in depth. We can bet 1 number, but 12 spins in depth. Both described bets are nominally identical. In both cases we will bet 12 numbers. But there is an important difference regarding the calculation of probabilities! When we turn the bet from the plane to the time vector, we get a wormhole. We can drill perpendicularly, static rebet, or at an angle or randomly. We can pull a narrow shaft on one number, or we can drill a wide shaft. Let's calculate P1 (12/37=0.324324) and P2 (1-(36/37)^12 = 0.280204). Do you see what I'm getting at?
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  • InquisitorEA
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Re: Hyperspace and Wormholes

1 month 3 weeks ago - 1 month 3 weeks ago
#2
Mathematics says that every person (without exception) loses in the long run. However, we meet people who live from roulette. So, you need to understand that in a casino you do not play against probabilities. And by the way, P2 probabilities should be added, not multiplied, then you will get a value equal to P1.

Re: Hyperspace and Wormholes

1 month 3 weeks ago - 1 month 3 weeks ago
#3
36/37 is the probability that the casino will beat the bet? (36/37) to the power of 12 is the probability that the casino will beat the bet 12 times in a row? One player's number wins in 12 spins = 1 - (36/37)^12 Why add it up?
If you bet on red in a casino and you're stubbornly unlucky, try betting on red!

 

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