To begin with, I will undertake to assert that the game of roulette is not a mathematical problem, but a logical puzzle. To make it clearer, I will add a simple example to the introduction to test attentiveness: 2 + 2x2

If you do not take into account the rules of addition and multiplication, you will get eight. Comparison with this simple example shows that by omitting some circumstances, any problem can be interpreted incorrectly. Has anyone wondered that in the solution - Is it possible to beat roulette? - the problem is initially incorrectly interpreted and formulated?
Let's start with what "serious" people do not discuss. With complete nonsense. With the "Two Thirds" law, it sounds like this: For 37 spins, out of 37 numbers on the roulette, only two thirds of these numbers will play. Some people don't consider this pattern to be a law, considering it to be something like a "consequence", but no matter how much you spin the ball, you can't change this law with the power of thought, unless you smash the roulette wheel with a hammer in your spare time. But we are not extreme people, so we will go the way of agreement and non-resistance, and accept it as a given, calling it not a law, but a pattern... Let's call it a pattern of all closed systems, a striking example of which is the game "Roulette". There are exactly 37 numbers, they will not decrease, they will not increase - the processes are closed, in a single cycle with an equally probable outcome. I'll dig even deeper. The pattern of "Two Thirds" is a universal rule that makes chance - random. If all 37 numbers fall out on the roulette wheel in 37 spins, then in order to win, it would be enough to bet on numbers that have not yet played. Or, if only one half of the available numbers fell out in 37 spins, it would be enough to bet on the numbers that had already played once. In both cases, the roulette would turn into a consistent system that can be easily predicted. Hence, “two thirds” for the unpredictability of chance is just right. Now, what’s the intrigue? The problem was formulated: There are 37 players at the gaming table. Each player has 37 chips. Each player, each spin, bets only on one number, one chip. Each player has his own number, for the entire period of the game and the player does not bet on other numbers. (Roulette 37 numbers, each player a number) The game lasts only 37 spins. Questions: On average, how many players will remain at a loss at the end of the game? On average, how many players will lose completely? On average, how many players will win more than they lose? The problem is not a trick, but rather a prelude to describe the essence of the theory. I propose to solve the problem by changing the priorities in it, expanding the interpretation of the discussed pattern. The pattern of "Two thirds" is not about the fact that in 37 spins only two thirds of the numbers will fall out. It is about the fact that a third of the numbers will not play because they will be displaced by repetitions. To get the average result - after calculating two thirds, we derive the exact number of numbers that did not play, and therefore we will get exactly the same number of repetitions. We will take the repetition as a unit of measurement and make an additional calculation with the obtained number. Having admitted the condition that in this number the same pattern of "Two thirds" works. In fact, we have a pattern in a pattern. The calculated sum of repetitions will also form two thirds of the numbers and one third will be displaced by repetitions-repetitions of these numbers. For example: if there were 12 repetitions, then there will be only eight numbers in this dozen, some of which will play three or four times. Now let's get back to understanding the problem: Of the 37 players, at the end of the game lasting 37 spins, we should have three groups and in the problem we need to determine the number of players in each of these groups (in fact, we do not count the players, but calculate the numbers). The numbers falling out on the roulette wheel are equally probable, therefore, the formation of groups is equally probable. And in the ideal model, in the answer, we should get two equally probable groups of losers, and one group of winners, adjusted for "regularity, in regularity" - the group of winners should be equal to two thirds of the number of the group of losers. It turned out to be something like "popular mechanics", but despite the fact that many will consider this definition useless, it hid another conclusion: Having an average result, we see in it that the "Two-thirds" law has nothing to do with the fact that on a roulette wheel, two thirds of the numbers will come up in a cycle of 37 spins, and there will be fewer of them. But during this cycle, more "repetitions" will occur, and there will be more than one third of them (attention: "repetitions", not repeated numbers). If we return to what I wrote at the beginning: that "two-thirds" is a universal rule that makes chance - random. If in a closed system the advantage is in one direction or another, we will get a consistent system, not a random one. And we get this "Paradox": if we follow the bets not for the numbers (I emphasize: not for the numbers), but for the "repetitions" * we will get, although not significant, an advantage. And vice versa, we will be in a more losing position if we bet on numbers that did not fall out. *How to follow "repeats"? - this is another conversation about another pattern, but I will immediately stipulate that this also has nothing to do with the "hot numbers" that casinos love to publish in their statistics. For general clarity, I will add: Repetitions are not tied to numbers, each new spin the candidates (numbers) change, and the numbers on which the bet is made may not have been repeated even once, but a characteristic repetition has already occurred and is stably occurring. And it is necessary to predict the repetition, and what this number will be, it is how the repetition will fall on it (This is a simplification, but in essence close to the original.) Sincerely, Vitaly Queenstar