Edwerk - order for a program, discuss strategy

Hello))) You drew 4 sectors. None of them have numbers that are on the same street together or next to each other on the same street. Sector 27 that you indicated looks like this: 6-13-27-34-36. 34 and 36 are located on the same twelfth street. And also, only one sector plays in one session, not two or three. Is it working out yet?)

In principle, there are no more questions - I give the command to the programmers and it will be done tomorrow. It will be convenient for us if the ENTIRE betting scheme is oriented towards "en plein", since this further opens up a lot of roads and options for development. There is no rigid binding to the standard playing field. In your case, this means that the street in the machine will be placed with 3 chips, i.e. each number by 1. Accordingly, the sector on the track will be placed 5 * 3 = 15 chips. In fact, this is x3 of the BR start you are used to, with full preservation of mathematics.

Eduard Bogdanov (Edwerk) Estonia

In ascending order on the field 11-13-27-30-36 = 0,10,13,14,15,25,26,28,29,34,35. 10-11-12 13-14-15 25-26-27 28-29-30 34-35-36 Why is there no 12 in the neighbors? It seems to be a typo, there should be 12 instead of 13 in the list of street neighbors.

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Another question. Are you sure that there are only 19 sectors (without two numbers on one street)? For example, your sectors with 36 in the composition: 11,8,13,30,36 13,6,11,27,36 30,8,11,23,36 36,11,13,27,30 What prevents you from also catching 34-6-27-13-36??? How is it worse?

SECRET Author: Eduard Bogdanov (Edwerk) sent an extended answer: Hello! Don't pay attention to the description of the system. I'll edit it later. The table is on the second sheet. Best regards, Eduard Bogdanov

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So, I present the "SECTOR" strategy. I had to suffer with rigged tables. But everything seems to be ok now, after I lost 500 Euro with it. Introduction and brief description. The scheme resembles the "Roulette Sequence" game system, but it is not so at the final stage! The bet starts with 12 chips on the field. 1 repeat of the bet in case of loss. Playing for the distance. Each bet (hit) on STREET returns our bet of 12 chips! Details of the "SECTOR" system 1) The playing numbers that fall under the forecast are the following: 1, 2, 6, 9, 11,12, 13, 14, 16, 17, 22, 23, 24, 25, 30, 31, 33, 35, 36. There are 19 playing numbers in total! Their neighbors do not meet twice on streets in European roulette. 2) The non-playing numbers, but participating in the system, are the following: 0, 3, 4, 5, 7, 8, 10, 15, 18, 19, 20, 21, 26, 27, 28, 29, 32, 34. There are 18 non-playing numbers in total! Their neighbors meet twice on streets in European roulette. Conditions for the forecast. From the very beginning of the game session, we start monitoring the 19 playing numbers, them and their four neighbors, two on each side! We monitor everyone at the same time. And when the prediction is triggered, it is displayed on the screen. There is no need to keep statistics, except for the last 3 numbers that have dropped out. Let there be space on the screen for the prediction for all 19 numbers, positions. The prediction is triggered when empty fields (including ZERO) have dropped out 11 times for the playing number (the same conditions for each playing sector) What are the "empty" fields for each playing number? To predict number 1 (sector 1-14-16-20-33), the following numbers must appear eleven times: 0, 2, 3, 13, 15, 17, 18, 19, 21, 31, 32. At the same time, any other numbers can appear as many times as you like, except for the number 1 and its neighbors on the wheel (14,16,20,33) and we do not count them for this sector. If one of the 5 winning numbers appears, we start counting 11 non-appearances for the number with the sector again, without betting on the table. If you miss, then make the same bet again, until you win or lose. If you hit a forced STREET, simply repeat the bet. With each bet on any sector, 11 numbers always remain uncovered! For greater clarity, I will give all the groups of numbers in the order of calculation that must fall 11 times (it is possible with repetitions of numbers) including all the other numbers in the group of neutral numbers: PLAYING SECTOR What numbers must fall 11 times before the forecast is issued 1,14,16,20,33 = 0,2,3,13,15,17,18,19,21,31,32. 2,4,17,21,25 = 0,1,3,5,6,16,18,19,20,26,27. 6,13,17,27,34 = 0,4,5,14,15,16,18,25,26,35,36. 9,14,18,22,31 = 0,7,8,13,15,16,17,23,24,32,33. 11,8,13,30,36 = 0,7,9,10,12,14,15,28,29,34,35. 12,1,7,28,35 = 0,1,2,8,9,10,11,29,30,34,36. 13,6,11,27,36 = 0,4,5,10,12,14,15,25,26,34,35. 14,1,9,20,31 = 0,2,3,7,8,13,15,19,21,32,33. 16,1,5,24,33 = 0,2,3,4,6,17,18,22,23,31,32. 17,2,6,25,34 = 0,1,3,4,5,16,18,26,27,35,36. 22,9,18,29,31 = 0,7,8,16,17,23,24,28,30,32,33. 23,5,8,10,30 = 0,4,6,7,9,11,12,22,24,28,29. 24,5,10,16,33 = 0,4,6,11,12,17,18,22,23,31,32. 25,2,17,21,34 = 0,1,3,16,18,19,20,26,27,35,36. 30,8,11,23,36 = 0,7,9,10,12,22,24,28,29,34,35. 31,9,14,20,22 = 0,7,8,13,15,19,21,23,24,32,33. 33,1,16,20,24 = 0,2,3,17,18,19,21,22,23,31,32. 35,3,12,26,28 = 0,1,2,10,11,25,27,29,30,34,36. 36,11,13,27,30= 0,10,13,14,15,25,26,28,29,34,35. These were all 19 playing numbers and their groups. If the sector 1-14-16-20-33 did not fall out 11 times while the neighbors of the numbers of the sector on the table fell out on the streets, taking into account the repetitions of those same numbers. But the sector itself did not fall out. 0 - we count as the number we need. The necessary example of the sequence of numbers that fell out: 0,29,35,0,26,15,15,4,24,36,3,7,12,21,8,2,19,0,6,13,25,32. Let's select the numbers we need that have dropped out: 0, 0, 15, 15, 3, 21, 2, 19, 0, 13, 32. TOTAL = 11 numbers. Start betting on the sector: 1-14-16-20-33 and 1 chip on the Streets: 2,3,4,8,9,10,12.

Answer: Sectors 28 and 29 are not included in the forecast. 23 and 24 are in play. But one of the two will come to the forecast first. Since the numbers next to them are still different. Namely: Sector 23 = 5,8,10,23,30.11 LOSS numbers: 0,4,6,7,9,11,12,22,24,28,29. Sector 24 = 5,10,16,24,33.11 LOSS numbers: 0,4,6,11,12,17,18,22,23,31,32. And now for dessert! Today I played live roulette and once again noticed how after a long wait for the entry point, after receiving a profit, chances pour in on the 3rd - 5th move like from a Horn of Plenty! And second. I have played 45 euros according to the system, and could have played 145. The trick is that the distance to 11 LOSS can vary every day. For example, today I played after the 7th LOSS and always won without progression. An hour or half an hour to collect statistics and we are on top)))) Connect the wisdom that is in your blood. Maybe you will be able to attach this adaptive mechanism to the program? You have absolutely correctly guessed the algorithm of the system. Can I send you the entire table for 19 playing sectors by e-mail? Give me the mail, please.

Let me ask the author a couple of questions first - 1) Do we control 32 sectors (5 numbers each) of the track? 14-20-1-33-16, 20-1-33-16-24, 1-33-16-24-5, etc. in a circle except for those that include 0. What to do with sectors that include 28-29 or 23-24, do they have a common street? 2) Wait for an event for the sector - a LOSS chain of the required length to activate the entry point. For a "sleeping" sector, we look at the statistics for a sample of numbers that lie with the sector numbers in the same street. We also count repeats as hits - we wait until 11 LOSS of such neighbors are collected in the streets of the base sector. 3) "0 - we count as the number we need" In the plan, it does not reset the entry point waiting cycle. 4) When the entry point appears (there are 11 LOSS in the streets of this sector), we start betting. On the track, we BET the sector itself and 1 chip in all streets where there are NO NUMBERS of the sector in question. *** If I misunderstood something, please clarify. Additional questions: What betting scheme do you suggest for 5 numbers + 7/8 streets? What BR start do you consider optimal? What results do you expect from such a game?